若圆x2+y2-2mx+m2=4和x2+y2+2x-4my=8-4m2相交，则实数M的取值范围是

资源ID：

若圆x^2+y^2-2mx+m^2=4和x2+y2+2x-4my=8-4m^2相交，则实数m的取值范围是

(x-m)^2+y^2=4
(x+1)^2+(y-2m)^2=9
所以圆心分御笑别是(m,0),(-1,2m)
半径是2和3
相交
则|r1-r2|d=√宏歼[(m+1)^2+(2m)^2]=√(5m^2+2m+1)
所以1<=√(5m^2+2m+1)<=5
1<=5m^2+2m+1<=25

1<=5m^2+2m+1
5m^2+2m>=0
m(5m+2)>=0
m<=-2/5,m>=0

5m^2+2m+1<=25
5m^2+2m-24<=0
(5m+12)(m-2)<=0
-5/12<=m<=2

所以-2/5<=m<=-5/蔽拆冲12,0<=m<=2