设A B为随机事件 P(A)=0.8 P(AB)=0.3 则P（A-B）=

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这个题型凯的关键在于弄清此租孝A-B的含义：事件森稿A发生且B不发生，AB的含义是事件A与B同时发生，所以很显然，P(A-B)=P(A）-P(AB)=0.8-0.3=0.5

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P(A-B)
=P(A)-P(AB)
=0.8-0.3
=0.5

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P(A)=0.8 P(AB)=0.3
P(A~B)(A与带薯液B非蠢物）=P(A)-P(AB)=0.5

P（A-B）手滚=P(A)-P(AB)=0.5

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