额定电压与额定功率分别是220V，40W和220V,100W的两盏电灯A和B

额定电压与额定功率分别是220V，40W和220V,100W的两盏电灯A和B，把它们串联起来接到110V的电压上，它们的实际功率Pa= Pb=

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RA = U*U /搜庆 RA = 220*220 / RA = 40 RA = 1210
RB = U*U / RB= 220*220 / RB = 100 RA = 484
串镇芦联后，R = RA+RB = 1694 I = 110/R= 110 /御漏带1694 = 0。065
Pa = I*I*RA = 0.065*0.065*1210= 5.1 W
Pb = I*I*RB = 0.065*0.065*484= 2.05 W

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RA = U*U / pA = 220v*220v / 40 w= 1210Ω
RB = U*U / pB= 220v*220v /绝模 100w = 484Ω
串联后冲李，R 总= RA+RB = 1694Ω
I = u/并判缓R= 110v /1694Ω = 0。065A
Pa = I*I*RA = 0.065A*0.065A*1210Ω= 5.1 W
Pb = I*I*RB = 0.065A*0.065A*484Ω= 2.05 W

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