(+1)+(-2)+(+3)+(-4)+......+(+99)+(-100)这道题怎么做

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(+1)+(-2)+(+3)+(-4)+......+(+99)+(-100)
前一位与后一位相加为－1，一共有御喊信镇轮50对

(+1)+(-2)+(+3)+(-4)+......+(+99)+(-100)＝－渗宴50

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=1-2+3-4+…笑团…+99-100
=(1-2)+(3-4)+…碰脊橘…+(99-100)
=(-1)+(-1)+…野圆…+(-1)
100个数，每两个一组，所以有50组
所以这里有50个(-1)
所以=(-1)×50=-50

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1-2=-1
3-4=-1
5-6=-1
……
这样两两分组，每组卖姿的结果为-1
因返含为有50组中世绝
所以答案为-50.

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(+1)+(-2)+(+3)+(-4)+......+(+99)+(-100)
=[(+1)+(-2)]+[(+3)+(-4)]+......+[(+99)+(-100)]
=-1×50
-50

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(+1)+(-2）=-1
(+3)+(-4)=-1
共50组
50*-1=-50

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1-2=-1
3-4=-1
5-6=-1
…岁咐卖…简棚
99-100=-1

所以乎逗(+1)+(-2)+(+3)+(-4)+......+(+99)+(-100)=-50

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