暖眸敏1V2013-02-09TA获得超过9.5万个赞关注∵(a²-3a-3-a³)-(a-8+4a²+2a³)+(3a³+3a²+4a-1)=a²-3a-3-a³-a+8-4a²-2a³+3a³+3a²+4a-1=(-1-2+3)a³+(1-4+3)a²+(-3-1+4)a+(-3+8-1)=4结果为常数∴该代数式的取值与a值无关