2x²y-xy²+y³=0方程所确定的隐函数y的导数dy/dx

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解：∵2x²唤迅谨y-xy²和基+y³=0 ==>4xydx+2x²dy-y²dx-2xydy+3y²dy=0
==>昌源(4xy-y²)dx=(2xy-2x²-3y²)dy
∴dy/dx=(4xy-y²)/(2xy-2x²-3y²)。

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