啊啊阿吖2010-12-23TA获得超过3173个赞关注(1+tanx)/(1-tanx)=3+2√2,解得tanx=√2/2.(sin^2x+√2sinx*cosx-cos^2x)/(sin^2x+2cos^2x)=(tan^2x+√2tanx-1)/(tan^2x+2)=(1/2+1-1)/(1/2+2)=1/5.