2x^2 + y^2 = 4
4x + 2ydy/dx = 0
dy = -2x/y
（1,√2）切线的斜率-2/√2 = -√2，法茄亩线斜率=1/√2
切线隐碧方程y-sqrt(2) = -sqrt(2)(x-1), sqrt(2)x + y = 2sqrt(2)
法线y-sqrt(2) = (x-1)/颤携森sqrt(2)
x - sqrt(2)y + 1 = 0
求椭圆曲线(x平方/2)+(y平方/4)=1上点（1,√2）处的切线方程和法线方程
2x^2 + y^2 = 4
4x + 2ydy/dx = 0
dy = -2x/y
（1,√2）切线的斜率-2/√2 = -√2，法茄亩线斜率=1/√2
切线隐碧方程y-sqrt(2) = -sqrt(2)(x-1), sqrt(2)x + y = 2sqrt(2)
法线y-sqrt(2) = (x-1)/颤携森sqrt(2)
x - sqrt(2)y + 1 = 0