求∫(1+sinx/1+cosx)*e^x的不定积分

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∫e^xdx/(1+cosx)+∫旁腊e^xsinxdx/(1+cosx)
=∫e^xdtan(x/2)+∫tan(x/运橡滑2)de^x
=e^x tan(x/2) -∫如耐tan(x/2)de^x+∫tan(x/2)de^x+C
=e^x tan(x/2) +C

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