化简：√1-2sin(π+2)cos(π+2)

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原式=√[1－2(－sin2)(－败碧轿慧差cos2)]
=√[1－察肆2sin2cos2]
=√[sin²a－2sin2cos2＋cos²2]
=√[sin2－cos2]²³
=|sin2－cos2|
=sin2－cos2

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