若1+2+3...+n=m,求(ab^n)*(a^2b^n-1)*.....(a^n-1b^2)*(a^nb)的值
坐等答案。
(ab^n)*(a^2b^n-1)*.....(a^n-1b^2)*(a^nb)
=a*a^2*…梁兆…*a^n*b*b^2…缓迅…扰渣此b^n
=a^(1+2+3...+n)*b^(1+2+3...+n)
=a^mb^m
a^mb^m
(ab)^m
若1+2+3...+n=m,求(ab^n)*(a^2b^n-1)*.....(a^n-1b^2)*(a^nb)的值
若1+2+3...+n=m,求(ab^n)*(a^2b^n-1)*.....(a^n-1b^2)*(a^nb)的值
坐等答案。
(ab^n)*(a^2b^n-1)*.....(a^n-1b^2)*(a^nb)
=a*a^2*…梁兆…*a^n*b*b^2…缓迅…扰渣此b^n
=a^(1+2+3...+n)*b^(1+2+3...+n)
=a^mb^m
a^mb^m
(ab)^m