
R1、R2并联时,则两端的电压相槐掘好等为U,
R1消耗的功率为P1=
| U2 |
| R1 |
| U2 |
| P1 |
R2消耗的功率为2P1=
| U2 |
| R2 |
| U2 |
| 2P1 |
| U |
| R2 |
所以R1=2R2;
R1、R2并联在电压为
| 3 |
| 2 |
通过R2的电流为I2′=I=
| ||
| R1+R2 |
| U |
| 2R2 |
R1两端的电压U1=IR1=
| U |
| 2R2 |
R2消耗的功率为P2=U2I=(
| 3 |
| 2 |
| U |
| 2R2 |
| U2 |
| 4R2 |
| U2 |
| 2R1 |
| 1 |
| 2 |
两个电阻消耗的总功率P=U总I=
| 3 |
| 2 |
| U |
| 2R2 |
| 3U2 |
| 4R2 |
| 3 |
| 2 |
故选B.

| U2 |
| R1 |
| U2 |
| P1 |
| U2 |
| R2 |
| U2 |
| 2P1 |
| U |
| R2 |
| 3 |
| 2 |
| ||
| R1+R2 |
| U |
| 2R2 |
| U |
| 2R2 |
| 3 |
| 2 |
| U |
| 2R2 |
| U2 |
| 4R2 |
| U2 |
| 2R1 |
| 1 |
| 2 |
| 3 |
| 2 |
| U |
| 2R2 |
| 3U2 |
| 4R2 |
| 3 |
| 2 |