因式分解a2-b2+2b-1 (a2d2为a的平方b的平方) 资源ID: 求过程谢谢各位大侠 a2-b2+2b-1=a2-(b2-2b+1)=a2-(b-1)2=(a-b+1)(a+b-1) a^2-b^2+2b-1=a^2-(b^2-2b+1)=a^2-(b-1)^2=(a+b-1)(a-b+1) a2-b2+2b-1=a2-(b2-2b+1) =a2-(b-1)2=(a+b-1)(a-b+1) a2-b2+2b-1=a2-(b2-2b+1)=a2-(b-1)2=(a+b-1)(a-b+1) ← 上一篇: 下一篇: →