lim(x趋向0)(1-cos2x)/xsinx怎么解?

---

lim(x趋向基陵轿0)(1-cos2x)/xsinx
=lim(x趋向0)[(1-1+2Sin^2(x)] /xsinx
=lim(x趋向汪链0)2sin^2x/xsinx
=lim(x趋搏肆向0)2sinx/x
=2

---

lim(x趋向轿咐败0)(1-cos2x)/(xsinx)
=lim(x趋向0)(2sin^2x)/简山(xsinx)
=lim(x趋闭颤向0)2sinx)/x
=2

---