已知x/3等于y/4等于z/5,求(3x－2y+6z)/(4x+5y)的值

---

设x/悔拆3=y/4=z/5=k
那么x=3k，y=4k，z=5k
于是(3x-2y+6z)/(4x+5y)
=(3*3k-2*4k+6*5k)/凯前庆(4*3k+5*4k)
=(9-8+30)/(12+20)
=31/盯握32

---

设X=3K Y=4K Z=5K
31/41

---