如题，要过程。。。急用啊。！！！！！！！！！
y'=xy-x^2+1,y'-xy=-x^2+1,解埋察齐次的先y'局笑-xy=0
y=C(x)e^(x^2/2)
带入桐液含C'(x)e^(x^2/2)+C(x)xe^(x^2/2)-C(x)xe^(x^2/2)=-x^2+1
C'(x)e^(x^2/2)=-x^2+1求出C(x)=∫e^(-x^2/2)(-x^2+1)dx
C(x)=xe^(-x^2/2)+C1
y=(xe^(-x^2/2)+C1)e^(x^2/2)且根据条件y(0)=1.0<=x<=1
C1=1,y=x+e^(x^2/2)