(2x-1)(x+3)<0
得x1=-3，x2=0.5
(-3,0.5)
x∈(-3,0.5)
数学高一解不等式，解集用区间表示。
(2x-1)(x+3)<0
得x1=-3，x2=0.5
(-3,0.5)
x∈(-3,0.5)
(2x-1)(x+3)<0
得x1=-3，x2=0.5
(-3,0.5)
x∈(-3,0.5)
(2x-1)(x+3)<0
得x1=-3，x2=0.5
(-3,0.5)
x∈(-3,0.5)
(2x-1)(x+3)<0
得x1=-3，x2=0.5
(-3,0.5)
x∈(-3,0.5)