求极限值, lim {(x^2-2x+4)/(x^2-3x-1)}^(2x-1)求解! (x趋于无穷)lim{(x^2-2x+4)/(x^2-3x-1)}^(2x

lim {(x^2-2x+4)/(x^2-3x-1)}^(2x-1)
=lim{[(x-1)^2+3]/[(x-1.5)^2-3.25]}^(2x-1)
=1

---

x^2-2x+4)/(x^2-3x-1）-1=(x+5)/(x2-3x-1)
(x+5)/(x2-3x-1)乘以2x-1的极限值2
所以这个函数的极限就是e的平方

---