6x^2y+2xy-3x^2y^2-7x-5yx-4y^2x^2-6x^2y，其中|x+3|+(y-2)^2=0

^2表示平方，！！！！！！！！急！！！！！！！！求答案和过程

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6x^2y+2xy-3x^2y^2-7x-5yx-4y^2x^2-6x^2y，
=-7x^2y^2-3xy-7x

其中|x+3|+(y-2)^2=0
即x+3=0,y-2=0
x=-3,y=2

原式=-7*9*4-3(-3)*2-7(-3)=-252+18+21=-213

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确定题目没有错吗？

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因为|x+3|+(y-2)^2=0
所兆昌以|x+3|=0，族租扒(y-2)^2=0。型历x=-3,y=2

6x^2y+2xy-3x^2y^2-7x-5yx-4y^2x^2-6x^2y，
=-3xy-7x^2y^2-7x
=213

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拜托你发张照片好了^^

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